Now, this one's a really interesting puzzle.
Players A and B each have a well shuffled standard pack of 52 cards. The players deal their cards one at a time, from the top of the deck, checking for an exact match. If the cards do not match, they put the two cards aside and then again deal one card each, from the top of their respective packs, and check for match. Player A wins if, once the packs are fully dealt, no matches are found. Player B wins if at least one match occurs. What is the probability that player A wins?
Players A and B each have a well shuffled standard pack of 52 cards. The players deal their cards one at a time, from the top of the deck, checking for an exact match. If the cards do not match, they put the two cards aside and then again deal one card each, from the top of their respective packs, and check for match. Player A wins if, once the packs are fully dealt, no matches are found. Player B wins if at least one match occurs. What is the probability that player A wins?
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my answer is 1 - (51/52)^52. ~ S K Mishra
@S K Mishra: This answer is not correct.
Just think carefully, this puzzle is an example of a very classic problem in probability.
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